统计出现两次以上目标个数函数怎么做?

[以Python为例]

以下是一个在Python中统计列表中出现两次以上元素个数的函数示例： ```python def count_more_than_twice(lst): counter = {} for num in lst: if num not in counter: counter[num] = 1 else: counter[num] += 1 result = 0 for value in counter.values(): if value >= 2: result += 1 return result

```

[以Java为例]

```java import java.util.HashMap; import java.util.Map;

class Main { public static int countMoreThanTwice(int arr) { Map counter = new HashMap<>(); for (int num : arr) { counter.put(num, counter.getOrDefault(num, 0) + 1); } int res = 0; for (int value : counter.values()) { if (value >= 2) { res++; } } return res; } } ```